what is the algorithm for this following code: # Display the…
Question Answered step-by-step what is the algorithm for this following code: # Display the… what is the algorithm for this following code: # Display the options with charges to user for toll collectionprint(“Following are the options for cars and their respective toll:”)CarOptions = { ‘Mini car’ : ‘AED 2’, ‘Sedan car’: ‘AED 3’, ‘SUV’ : ‘AED 4’, ‘Truck/Bus/Coach’ : ‘AED 8’, ‘Emergency vehicle’: ‘AED 0’, ‘See result’: ‘ ‘, ‘Exit program’: ‘ ‘}Carlist = [‘Mini car’, ‘Sedan car’, ‘SUV’, ‘Truck/Bus/Coach’, ‘Emergency vehicle’]for i, j in CarOptions.items(): print(i, “”, j)# Ask the user to enter the option number for the car passedexit_program = 7while True: car_passed = int(input(“Please enter the option number for the car passed: “)) # If a user enter option 6 then the program will generate result if car_passed == 6: print(“Salik Collected Toll for Today”) for i in Carlist: total = {‘Mini car’: 0, ‘Sedan car’: 0, ‘SUV’: 0, ‘Truck/Bus/Coach’: 0, ‘Emergency Vehicle’: 0} if total [i] > 0: salik = str(total[i]) + ” ” + i + “s passed-” + str(total[i]) + “*” + CarOptions[i][-1] + “= ” + str(total[i] * int(CarOptions[i][-1])) + “AED Toll Collected” print(salik) if car_passed <= 5: print(Carlist[car_passed - 1] + " passed and a toll of " + CarOptions[Carlist[car_passed - 1]] + " was collected") # Ask the user to enter how many times did the option car passed times_car_passed = int(input("please enter how many times " + Carlist[car_passed - 1] + " passed: ")) if Carlist[car_passed - 1] == 'Mini car': result = times_car_passed * 2 elif Carlist[car_passed - 1] == 'Sedan Car': result = times_car_passed * 3 elif Carlist[car_passed - 1] == 'SUV': result = times_car_passed * 4 elif Carlist[car_passed - 1] == 'Truck/Bus/Coach': result = times_car_passed * 8 elif Carlist[car_passed - 1] == 'Emergency vehicle': result = times_car_passed * 0 iResult = ('Salik Collected Toll for Today: ' + str(result) + " AED") print(iResult) if car_passed == exit_program: # In case option 7 is pressed then the program should write all details in a text file and stop execution handle = open("CommonAssesment1.py", "w") text = handle.writelines() handle.close() print(text) break Computer Science Engineering & Technology Python Programming Share QuestionEmailCopy link Comments (0)
