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Question Answered step-by-step Please type the answers or if you are forced to handwrite them,… Please type the answers or if you are forced to handwrite them, please make sure it is legible and easy to follow. Thank you so much for your help!9.5 Q2Image transcription textConsider the following hypothesis test: HI}: p 2 0.75 Ha: p <1 0.75 A sample of 200 items was selected. Compute the p—value and state your conclusion for each of the following sample results. Use a: = 0.05. Round your answers to four decimal places. a. 5 = 0.53 p-value 11.11110 0 Conclusion: p-UEIUE less than or equal In 0.05, reject V 9 Ha I}. r; = 0.72 p-value 11.1635 @ Conclusion: p-UEIUE greater than 0.05, do not reject V 9 Ha c. 5 = 0.59 p-value 11.0250 @ Conclusion: p-VEIUE less than or equal In 0.05, reject V 9 HI] d. r; = 0.73 p-value 0.8340 8... Show more 11.2 Q1Image transcription textConsider the following hypothesis test. Ho : 01 = 07 H. : 01 707 a. What is your conclusion if n1 = 21, s; = 8.2, n2 = 26, and $; = 4.07 Use a = 0.05 and the p-value approach. Calculate the value of the test statistic (to 2 decimals). 2.05 The p-value is between 0.05 and 0.10 v . Use Table 4 of Appendix B. What is your conclusion? Cannot conclude that the two population variances are different v b. Repeat the test using the critical value approach. What is the rejection rule for this hypothesis test? Round the critical values to 2 decimal places. Reject Ho if F greater than or equal to 2.01 What is your conclusion? Cannot conclude that the two population variances are different v... Show more11.2 Q2Image transcription textConsider the following hypothesis test. Ho : 61 = 07 a. What is your conclusion if n1 = 21, s; = 8.2, n2 = 26, and $; = 4. Use a = 0.05 and the p-value approach. Calculate the value of the test statistic (to 2 decimals). 2.05 The p-value is between 0.05 and 0.10 v . Use Table 4 of Appendix B. What is your conclusion? Cannot conclude that the two population variances are different v b. Repeat the test using the critical value approach. What is the rejection rule for this hypothesis test? Round the critical values to 2 decimal places. Reject Ho if F greater than or equal to V What is your conclusion? Cannot conclude that the two population variances are different v... Show more13.3 Q1Image transcription textb. Calculate the value of Fisher's LSD (to 2 decimals). 3.23 Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion CA - CB 15 Significant difference V CA- CO 6 Significant difference V CB - C0 9 Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers. 11.7718.23... Show more13.3 Q2Image transcription textb. Calculate the value of Fisher's LSD (to 2 decimals). 3.23 Use Fisher's LSD procedure to test whether there is a significant difference between the means for treatments A and B, treatments A and C, and treatments B and C. Use a = 0.05. Difference Absolute Value Conclusion CA - CB 17 Significant difference CA - CC 7 Significant difference CB - C0 10 Significant difference c. Use Fisher's LSD procedure to develop a 95% confidence interval estimate of the difference between the means of treatments A and B (to 2 decimals). Enter negative values as negative numbers. 13.7720.23... Show more15.2 Q1Image transcription textConsider the following data for a dependent variable y and two independent variables, a1 and T2. Click on the datafile logo to reference the data. DATA file C1 C2 30 12 94 47 10 108 25 17 112 51 16 178 40 5 94 51 19 175 74 7 170 36 12 117 59 13 142 76 16 211 Round your all answers to two decimal places. Enter negative values as negative numbers, ifnecessary.... Show moreImage transcription textRound your all answers to two decimal places. Enter negative values as negative numbers, if necessary. a. Develop an estimated regression equation relating y to $1. Predict y if $1 = 45. = b. Develop an estimated regression equation relating y to $2. Predict y if *2 = 15. c. Develop an estimated regression equation relating y to a1 and $2. = + 2.01 4.74 C2 Predict y if 21 = 45 and $2 = 15. 1 =143.18... Show more15.2 Q2Image transcription textConsider the following data for a dependent variable y and two independent variables, @1 and 2. C1 C2 y 29 12 95 46 11 108 24 18 113 50 16 179 40 5 95 51 19 176 75 7 170 36 12 117 60 13 142 77 17 211 Round your all answers to two decimal places. Enter negative values as negative numbers, if necessary.... Show moreImage transcription textRound your all answers to two decimal places. Enter negative values as negative numbers, if necessary. a. Develop an estimated regression equation relating y to $1. + C1 Predict y if $1 = 35. b. Develop an estimated regression equation relating y to $2. = + Predict y if $2 = 25. c. Develop an estimated regression equation relating y to @1 and $2. + 1.91 c1 + Predict y if $1 = 35 and *2 = 25.=... Show more15.6 Q1Image transcription textThe owner of Showtime Movie TheatersI Inc.I used multiple regression analysis to predict gross revenue {3:} as a function of television advertising (31) and newspaper advertising {$3}. Values of y, 31, and 33 are expressed in thousands of dollars. Click on the datafile logo to reference the data. DATA till i 8 Weekly Gross Television Newspaper Revenue Advertising Advertising (31000:!) (310005) (310005) 96 5.0 1.5 90 2.0 2.0 95 4.0 1.5 92 2.5 2.5 95 3.0 3.3 94 3.5 2 .3 94 2.5 4.2 94 3.0 2 .5 The estimated regression equation was 3} = 33.23 + 2.29.761 + 1.30:6] a. 1Nhat is the gross revenue expected for a week where $3,500 is spent on television (21 = 3.5} and $1,300 is spent on newspaper advertising {32 = 1.8} {to 3 decimals)? 5|;thousand ... Show more Image transcription textThe estimated regression equation was 3} = 8323 + 2293.1 + L303; a. What is the gross revenue expected for a week where $3,501] is spent on television {31 = 3.5} and $1,801] is spent on newspaper advertising (a; = 1.8} {to 3 decimals)? :1; thousand h. Provide a 95% prediction interval for next week's revenue. assuming that the advertising expenditures will be allocated as in part (a) {to 2 decimals). ($ thousand, $ thousandJ ... Show more15.6 Q2Image transcription textThe owner of Showtime Movie Theaters, Inc., used multiple regression analysis to predict gross revenue {y} as a function of television advertising (31) and newspaper advertising [33). Values ofy, a1, and 33 are expressed in thousands of dollars. Weekly Gross Television Newspaper Revenue Advertising Advertising (31000:!) (31000:!) (31000:!) 95 5.0 1.5 90 2.0 2.0 95 4.0 1.5 92 2.5 2.5 95 3.0 3.3 94 3.5 2.3 94 2.5 4.2 94 3.0 2.5 The estimated regression equation was 3} = 33.23 + 2.29161 + 1.30% a. What is the gross revenue expected for a week where $3,500 is spent on television {31 = 3.5) and $1,300 is spent on newspaper advertising (:52 = 1.8} {to 3 decimals)? :1: thousand I]. Provide a 95% prediction interval for next week's revenue, assuming that the advertising expenditures will be allocated as in part {a} {to 2 decimals). C $ thousand, $thousand) ... Show more15.8 Q1Image transcription textData for two variables, + and y, follow. 22 24 25 28 41 12 23 31 35 70 a. Develop the estimated regression equation for these data (to 2 decimals). Enter negative value as negative number. y = + b. Compute the standardized residuals for these data (to 2 decimals). Do not round your intermediate calculations. Enter negative value as negative number. Standardized yi Residual 22 12 24 23 25 31 28 35 41 70 -0.30 Can any of these observations be classified as an outlier? Explain.No... Show more Math Statistics and Probability BUS 308 308 Share QuestionEmailCopy link Comments (0)
