According to the empirical rule, approximately what percentage of normally distributed data lies within one standard deviation of the mean? a) 59% b) 68% c) 72% d) 95% e) 99.7%

/in /by

According to the empirical rule, approximately what percentage of normally distributed data
lies within one standard deviation of the mean?
a) 59%
b) 68%
c) 72%
d) 95%
e) 99.7%

You might also like
The table lists the smoking habits of a group of college students. Sex Non-smoker Regular Smoker Heavy Smoker Total Male 176 47 31 254 Female 196 31 19 246 Total 372 78 50 500 If a student is chosen at random, find 1- The probability of getting a male. 2- The probability of getting a female given that she was a regular smoker. 3- The probability of getting someone who is a male or a non-smoker.
Let X and Y be two continuous random variables with joint pdf 2 f(x, y) = cx y(1 + y) for 0 ≤ x ≤ 3 and 0 ≤ y ≤ 3, and f(x, y) = 0 otherwise. (a) Find the value of c. (b) Find the probability P(1 ≤ X ≤ 2, 0 ≤ Y ≤ 1). (c) Determine the joint cdf of X and Y for a and b between 0 and 3. (d) Find marginal cdf FX(a) for a between 0 and 1. (e) Find the marginal pdf fX(x) directly from f(x, y) and check that it is the derivative of FX(x).
Choose the correct answer 4) “The names of 70 contestants are written on 70 cards. The cards are placed in a bag, and three names are picked from the bag” the statement descried. 1) Random sample 2) Systematic sample 3) Stratified sample 4) Cluster sample
The following sample observations were randomly selected X 4 5 3 6 10 Y 4 6 5 7 7 a) Determine the correlation coefficient and interpret the relationship between X and Y. b) Determine the regression equation c) Determine the value of when X is 7. d) State two uses of goodness-of-fit test
A committee of 5 people is to be formed randomly from a group of 10 women and 6 men. Find the probability that the committee has
The runs scored in a cricket match by 11 players is as follows: 7, 16, 121, 51, 101, 81, 1, 16, 9, 11, 16 Find the mean, mode, median of this data.
Let X1, X2, . . . , X81 be i.i.d., each with expected value µ = E(Xi) = 5, and variance σ2 = Var(Xi) = 4. Approximate P(X1 + X2 +· · · X81 > 369), using the central limit theorem.
Factorial 0 is equal to a) 0 b) 0.1 c) 1 d) -1