A Biology professor is teaching sections A and B of BIOL 1000. The…

Question Answered step-by-step A Biology professor is teaching sections A and B of BIOL 1000. The… A Biology professor is teaching sections A and B of BIOL 1000. The professor knows from thepast that the student exam marks of section A follows a normal distribution with an average of65, and a standard deviation of 10 while the student’s exam marks of section B follows a normaldistribution with an average of 70, and a standard deviation of 20.a) Find the probability that the average exam marks by a random sample of 100 students insection B is less than 67.b) What is the probability that the average exam marks of 81 randomly selected studentsfrom section A is one mark higher than the average exam marks of 100 randomlyselected students from section B?c) The professor declares that no more than one-quarter of section B’s students will getaverage marks. What is the probability that in a random sample of the 80 section Bstudents, more than 28 will get the average marks?d) (Solve this part independently). A random sample of 6 National bank employees was taken tohelp estimate the average amount of time(x) employees spent per week on their cell phones. Thesample data and some relevant information are listed below:13, 5, 6, 10,7, 12.Ex = 53, Sample Variance of x = 10.9667Find an unbiased estimator of the average time per week for all bank employees. Math Statistics and Probability ADMS 2320 Share QuestionEmailCopy link Comments (0)