9% of all Americans suffer from sleep apnea. A researcher suspects…

Question Answered step-by-step 9% of all Americans suffer from sleep apnea. A researcher suspects… 9% of all Americans suffer from sleep apnea. A researcher suspects that a different percentage of those who live in the inner city have sleep apnea. Of the 310 people from the inner city surveyed, 37 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.01?For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be:     Ho: ? μ p  Select an answer = ≠ > <   (please enter a decimal)    H1: ? p μ  Select an answer ≠ < = >   (Please enter a decimal)The test statistic ? z t  =  (please show your answer to 3 decimal places.)The p-value =  (Please show your answer to 4 decimal places.)The p-value is ? ≤ >  ααBased on this, we should Select an answer reject accept fail to reject  the null hypothesis.Thus, the final conclusion is that …Interpret the p-value in the context of the study.Interpret the level of significance in the context of the study. If the population proportion of inner city residents who have sleep apnea is 9% and if another 310 inner city residents are surveyed then there would be a 1% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is different from 9%.There is a 1% chance that aliens have secretly taken over the earth and have cleverly disguised themselves as the presidents of each of the countries on earth.If the population proportion of inner city residents who have sleep apnea is different from 9% and if another 310 inner city residents are surveyed then there would be a 1% chance that we would end up falsely concluding that the proportion of all inner city residents who have sleep apnea is equal to 9%.There is a 1% chance that the proportion of all inner city residents who have sleep apnea is different from 9%. If the population proportion of inner city residents who have sleep apnea is 9% and if another 310 inner city residents are surveyed then there would be a 7.1% chance that either more than 12% of the 310 inner city residents have sleep apnea or fewer than 6% of the 310 inner city residents have sleep apnea.There is a 7.1% chance of a Type I error.If the sample proportion of inner city residents who have sleep apnea is 12% and if another 310 inner city residents are surveyed then there would be a 7.1% chance that we would conclude either fewer than 9% of all inner city residents have sleep apnea or more than 9% of all inner city residents have sleep apnea.There is a 7.1% chance that the percent of all inner city residents who have sleep apnea differs from 9%. The data suggest the population proportion is not significantly different from 9% at αα = 0.01, so there is not sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is different from 9%.The data suggest the populaton proportion is significantly different from 9% at αα = 0.01, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is different from 9%The data suggest the population proportion is not significantly different from 9% at αα = 0.01, so there is sufficient evidence to conclude that the population proportion of inner city residents who have sleep apnea is equal to 9%.  Math Statistics and Probability MATH 220 Share QuestionEmailCopy link Comments (0)