Solve in a three decimal places. Answer it completely with step by…

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Question Answered step-by-step Solve in a three decimal places. Answer it completely with step by… Solve in a three decimal places. Answer it completely with step by step solution… QUESTION:Image transcription textFlexural Members Instructions: Using aW21x44 beam to support the loads,determine the maximum u… Show more… Show moreREFERENCE:Image transcription textA. CONSIDERING BENDING ($1) 4 = unbraced length = 2500 mm4p = 1.76 ry Fy = 1.76 ( 32) 20OK 248 Lp = 1599.38 < Lb -consider Ir 1 = 1.95 r E JC 1+ 1+6.76 / 0.70Fy Sx ho 1... Show more... Show moreImage transcription textSAMPLE PROBLEM : 121 x 44 A W21x44 beams support theload d= 524.76 mm shown. Assume ABG steel . The beamscompression bf = 145. 10mm flange has lateral supp... Show more... Show moreImage transcription text- computation of G: consider the unbraced length (critical) 1.875w+ 2250 can be computed 1.25w + 22. 570 using ratio &proportion 0.625 + 22.50 2.50w+ 22.50 02.50 1 A2 3... Show more... Show moreImage transcription textL. considering shear ( see pp 307-308 For reference ) Vmax = Vu =SW+ 22.5 Vn = $ 0.60 Fy Aw CV ; $ = 1.0 12 = 1:50 FOR Aw = d(two ) rox G: 1 = T _ d-2k = 524.76 (B89) two = 4665. 1... Show more... Show more  Engineering & Technology Civil Engineering CIV E 270 Share QuestionEmailCopy link Comments (0)