P1 = 437 + 32 = 437 + 1(32) P2 = P1 + 32 = 437 + 32 + 32 = 437 +… P1 = 437 + 32 = 437 + 1(32)P2 = P1 + 32 = 437 + 32 + 32 = 437 + 2(32)P3

P1 = 437 + 32 = 437 + 1(32) P2 = P1 + 32 = 437 + 32 + 32 = 437 +… P1 = 437 + 32 = 437 + 1(32)P2 = P1 + 32 = 437 + 32 + 32 = 437 + 2(32)P3 = P2 + 32 = (437 + 2(32)) + 32 = 437 + 3(32)P4 = P3 + 32 = (437 + 3(32)) + 32 = 437 + 4(32)You can probably see the pattern now, and generalize thatPn = 437 + n(32) = 437 + 32nUsing this equation, we can calculate how many bottles he’ll have after 5 years:P5 = 437 + 32(5) = 437 + 160 = 597We can now also solve for when the collection will reach 1000 bottles by substituting in1000 for P n and solving for n1000 = 437 + 32n563 = 32nn = 563/32 = 17.59 where did 563 come from? Math Linear Algebra MTH 105 Share QuestionEmailCopy link