7. (15 pts) .Suppose _8.00_ mL of a solution of FeCl 3. could be…

/in /by

Question Answered step-by-step 7. (15 pts) .Suppose _8.00_ mL of a solution of FeCl 3. could be… 7.  (15 pts) .Suppose _8.00_ mL of a solution of FeCl3. could be titrated with NaOH like CoCl2. was in this experiment.  If _15.00_ mL of _0.51_ M NaOH was needed to arrive at the end point, calculate the molarity of the FeCl3. solution.  Show your work. FeCl3+NaOH à Fe(OH)3+NaClFe(OH)=> weight => 0.51            0.51/162.2 g/molMole of Fe(OH)= 0.0031Molarity of FeCl = 0.0031×15/1000 = 4.65×10-5  Did I do the correct work? plug the correct numbers? Chemistry Science Organic chemistry CHM 152 Share QuestionEmailCopy link Comments (0)